University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 13 - Practice Exercises - Page 749: 9

Answer

$-2$

Work Step by Step

We need to find the limit for $\lim\limits_{(x,y) \to (\pi,\ln 2)} e^y \cos x$ or, $=e^{\ln 2} (\cos \pi)$ Thus, $\lim\limits_{(x,y) \to (\pi,\ln 2)} e^y \cos x=(2) (-1)=-2$
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