Answer
$y= x^2-2x$; $v(1)=i+2j$ and $a(1)=2j$
Work Step by Step
Since, we have $x=t+1; y=t^2-1$
and, $t^2-1=(t-1)(t+1)$
This can be written as:
$y=(x-2)x \implies x^2-2x$
Now, velocity $v(t)=r'(t)=i+2tj$
and $v(1)=i+2j$
As we know acceleration $a(t)=v'(t)=2j$
and $a(1)=2j$
Hence, we have $y= x^2-2x$; $v(1)=i+2j$ and $a(1)=2j$
