University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 11 - Section 11.6 - Cylinders and Quadric Surfaces - Exercises - Page 636: 11


Elliptical cone (graph h).

Work Step by Step

Since, we have $x^2+4z^2=y^2$ This can be re-written as: $\dfrac{x^2}{1}+\dfrac{z^2}{(1/2)^2}=\dfrac{y^2}{1}$ Since, the equation is a graph for an Elliptical cone along the y-axis as shown in graph (h).
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