#### Answer

$x=1,y=2-t, z=-t$

#### Work Step by Step

The parametric equations of a straight line can be found by knowing the value of a vector, such as $v=v_1i+v_2j+v_3k$, passing through a point $P(x_0,y_0,z_0)$ as follows:
$x=x_0+t v_1,y=y_0+t v_2; z=z_0+t v_3$
Here, we have $P(1,2,0)$ and $v=\lt 1-1,1-2,-1-0 \gt =\lt 0,-1,-1 \gt$
Thus, we get the parametric equations:
$x=1,y=2-t, z=-t$