University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 11 - Section 11.3 - The Dot Product - Exercises - Page 618: 49

Answer

$8.13^{\circ}$ or $0.14$ rad

Work Step by Step

The result of exercise 31 tells us that ${\bf v}=\langle a,\ b \rangle$ is perpendicular to lines $ax+by=c$ ${\bf n_{1}}= \langle 3,-4\rangle$ is perpendicular to $3x-4y=3$ ${\bf n_{2}}=\langle 1,-1\rangle$ is perpendicular to $x-y=7.$ $\displaystyle \theta=\cos^{-1}(\frac{{\bf n_{1}}\cdot{\bf n_{2}}}{|{\bf n_{1}}||{\bf n_{2}}|})$ $=\displaystyle \cos^{-1}(\frac{3+4}{\sqrt{3+16}\cdot\sqrt{1+1}})$ $=\displaystyle \cos^{-1}(\frac{7}{5\cdot\sqrt{2}})\approx 8.13^{\circ}$ or $0.14$ rad
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