University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 11 - Section 11.3 - The Dot Product - Exercises - Page 617: 32

Answer

Proof given below.

Work Step by Step

If the line has slope defined, then $a\neq 0$ and $y=\displaystyle \frac{b}{a}x-c$, the slope of the line is $\displaystyle \frac{b}{a}.$ The slope of ${\bf v}$=$\langle a,\ \ b \rangle$ is also $\displaystyle \frac{b}{a}$, when $a\neq 0$. So, for $a\neq 0,\ {\bf v}$ is parallel to the line. If $a=0$, the vector ${\bf v}$ has undefined slope (parallel to ${\bf j}).$ If $a=0$, the line $\quad bx=c\quad $is vertical, parallel to the y-axis. ${\bf v}$ is parallel to the line in this case as well..
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.