University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 11 - Section 11.3 - The Dot Product - Exercises - Page 616: 16

Answer

$1.55$ or $\approx 88.88 ^{\circ}$

Work Step by Step

The formula to calculate the angle between two planes is: $ \theta = \cos ^{-1} (\dfrac{p \cdot q}{|p||q|})$ Here, $u=\lt 0,1,0.2 \gt$ and $v=\lt 1,0,0.1 \gt$ $|u|=\sqrt{(0)^2+(1)^2+(0.2)^2}= \sqrt {1.04}$ and $|v|=\sqrt{(1)^2+(0)^2+(0.1)^2}=\sqrt {1.01}$ Thus, $ \theta = \cos ^{-1} (\dfrac{u \cdot v}{|u||v|})=\cos ^{-1} (\dfrac{0.2}{ ( \sqrt {1.04})(\sqrt {1.01}})$ or, $ \theta \approx 1.55$ or $\approx 88.88 ^{\circ}$
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