University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 10 - Section 10.6 - Conics in Polar Coordinates - Exercises - Page 591: 32


$r=\dfrac{8}{1+2\cos \theta}$

Work Step by Step

The polar equation of a conic with eccentricity $e$ and directrix $x=k$ is defined as: $r=\dfrac{ke}{1+e \cos \theta}$ ...(1) We are given that the vertices are: $e=2,k=4$ Then $x=4$ Thus, equation (1), becomes $r=\dfrac{8}{1+2\cos \theta}$
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