Answer
$x=2- \cos \theta$;$y=\sin \theta$; $0\leq \theta \leq 2 \pi$
Work Step by Step
The equation is a circle shifted from $(0,0)$ to $(2,0)$. Thus, we have:
$y=\sin \theta$
$x=2- \cos \theta$
Hence, $x=2- \cos \theta$; $y=\sin \theta$; $0\leq \theta \leq 2 \pi$
