Answer
$\dfrac{dy}{dx}=y$ ; $y(0)=1$
Work Step by Step
Take derivative of the given differential equation.
This implies that
$\dfrac{dy}{dx}=0+y(x)$
or, $\dfrac{dy}{dx}=y$
Now, apply the initial conditions.
Hence, we get $y(0)=1$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 9: First-Order Differential Equations - Section 9.1 - Solutions, Slope Fields, and Euler's Method - Exercises 9.1 - Page 531: 10
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