Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 7: Transcendental Functions - Practice Exercises - Page 441: 119

Answer

$\frac{1}{e}$ $m/sec$

Work Step by Step

$\frac{dy}{dx}$ = $\frac{1}{x}$ $\frac{dx}{dt}$ = $\sqrt x$ $\frac{dy}{dt}$ = $\frac{dy}{dx}$ $\frac{dx}{dt}$ = $\frac{1}{x}(\sqrt x)$ = $\frac{1}{\sqrt x}$ $\frac{dy}{dt}$$|_{{\,e^{2}}}^{{\,}}$ = $\frac{1}{e}$ $m/sec$
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