Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 15: Multiple Integrals - Section 15.5 - Triple Integrals in Rectangular Coordinates - Exercises 15.5 - Page 901: 23

Answer

$\frac{2}{3}$

Work Step by Step

$ V=\int^1_0 \int^1_{-1} \int^{y^2}_0$ dz dy dx =$\int^1_0 \int^1_{-1}y^2 dy $ dx =$\frac{2}{3}\int^1_0 dx $ =$\frac{2}{3}$
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