Answer
$y=c_{1}+c_{2}e^{-3x}$
Work Step by Step
$y''+3y'=0$
Use auxiliary equation
$r^{2}+3r=0$
$r^{2}+3r=0$
$r(r+3)=0$
$r=0, -3$
Theorem 4
$y=c_{1}e^{r_{1}x}+c_{2}e^{r_{2}x}$
$y=c_{1}e^{0x}+c_{2}e^{-3x}$
$y=c_{1}+c_{2}e^{-3x}$
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