Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 15 - Multiple Integrals - 15.10 Exercises - Page 1071: 3

Answer

$-\cos (2\theta)$

Work Step by Step

$Jacobian =\begin{vmatrix} \dfrac{\partial x}{\partial r}&\dfrac{\partial x}{\partial \theta}\\\dfrac{\partial y}{\partial r}&\dfrac{\partial \theta}{\partial v}\end{vmatrix}$ Now, $Jacobian =\begin{vmatrix} -e^r \sin \theta&-e^{-r} \cos \theta\\e^r \cos \theta&-e^r \sin \theta\end{vmatrix}=\sin^2 \theta-\cos^2 \theta=-\cos (2\theta)$
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