Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 14 - Partial Derivatives - 14.6 Exercises - Page 967: 4

Answer

$\dfrac{7}{2}(\sqrt3+1)$

Work Step by Step

Formula to calculate the directional derivative: $D_uf=f_x(x,y)a+f_y(x,y)b$ $D_uf=(3x^2y^4+4x^3y^3) \times \cos (\pi/6)+(4x^3y^3+3x^4y^2) \times \sin (\pi/6)$ This implies At $(1,1)$ $D_uf(1,1)=7 \times \dfrac{\sqrt 3}{2}+7 \times \dfrac{1}{2}$ $D_uf(1,1) =\dfrac{7}{2}(\sqrt3+1)$
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