Answer
TRUE
Work Step by Step
$0.99999...=0.9+0.09+0.099+..$
$=\Sigma _0^\infty\frac{9}{10}\times (\frac{1}{10})^{n}$
$=\frac{9/10}{1-\frac{1}{10}}$
$=1$
Hence, the statement is true.
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