Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 11 - Infinite Sequences and Series - 11.2 Exercises - Page 736: 57

Answer

The series is convergent and the sum is $\frac{-5x}{1+5x}$.

Work Step by Step

$\Sigma^{\infty}_{n=1} (-5)^{n}x^{n} = \Sigma^{\infty}_{n=1}(-5x)^{n}$ $a=-5x$ and $r=-5x$ $|r| \lt 1$ $|-5x| \lt 1$ $|5x| \lt 1$ $-\frac{1}{5} \lt x \lt \frac{1}{5}$ Therefore the series converges, and the sum is $\Sigma^{\infty}_{n=1} (-5x)^{n} = \frac{a}{1-r}$ $=\frac{-5x}{1+5x}$
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