Answer
This polar equation describes a line with slope $\sqrt 3$ that passes through $(0,0)$.
Work Step by Step
$\theta = \pi/3$
$tan (\theta) = tan (\pi /3)$
$tan(\theta) = \sqrt 3$
- Remember: $tan(\theta) = \frac y x$
$\frac y x = \sqrt 3$
$y = \sqrt 3 x$
- This Cartesian equation follows the pattern for lines:
$y = ax + b$
In this case: $a = \sqrt 3$ and $b = 0$. Since $b =0$, the lines passes through (0,0).
