## Multivariable Calculus, 7th Edition

a) Check graph. As t increases, y increases. As t increases, x initially increases and then decreases again back to its original position. b) $y=\sqrt(-x+1)-2$ or $x=-(y+2)^{2}+1$
a) $x=1-t^{2}$, $y=t-2$, $-2 \leq t \leq 4$ When, t=-2 x=-3 y=-4 t=-1 x=0 y=-3 t=0 x=1 y=-2 t=1 x=0 y=-1 t=2 x=-3 y=0 t=3 x=-8 y=1 t=4 x=-15 y=1 b) $x=1-t^{2}$ $\sqrt (-x+1)=t$ $y=t-2$ $y=\sqrt(-x+1)-2$ or $x=-(y+2)^{2}+1$ From part A, we can infer that $-4 \leq y \leq0$