Answer
$P(x)\approx 25.13(1.064)^{x}$
Work Step by Step
For small x,
$f(x)=\displaystyle \frac{N}{1+Ab^{-x}}\approx(\frac{N}{1+A})b^{x}$
the logistic function grows approximately exponentially with base b.
From the given model,
$N=95.0,\ A=2.78, b=1.064$
so for small x,
$P(x)\displaystyle \approx\frac{95.0}{3.78}(1.064)^{x}\approx 25.13(1.064)^{x}$
$P(x)\approx 25.13(1.064)^{x}$
