Answer
$I_{1}=I_{o}\cdot 10^{0.1D_{1}}$
$I_{2}=I_{o}\cdot 10^{0.1D_{2}}$
$\displaystyle \frac{I_{2}}{I_{1}}=\frac{I_{o}\cdot 10^{0.1D_{2}}}{I_{o}\cdot 10^{0.1D_{2}}}=\frac{10^{0.1D_{2}}}{10^{0.1D_{2}}}\qquad $
(use the rule $\displaystyle \frac{a^{m}}{a^{n}}=a^{m-n} )$
$\displaystyle \frac{I_{2}}{I_{1}}=10^{0.1D_{2}-0.1D_{1}}$
$\displaystyle \frac{I_{2}}{I_{1}}=10^{0.1(D_{2}-D_{1})}$
Work Step by Step
No extra steps.
