Answer
$P=0.153(1.09)^{t}$ million dollars
where t = years after 1994
Work Step by Step
Using desmos.com, we enter the table with variables t and P
We enter in a free cell
$P\sim Ab^{t}$
place tick in "log mode" to obtain an exponential regression formula tying P to t, and the calculator returns (see image):
$A=0.153, b=1.09$
with the correlation coefficient $r$ being relatively close to $1$, indicating a good fit.
The model is
$P=0.153(1.09)^{t}$
where t = years after 1994