Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 9 - Section 9.2 - Exponential Functions and Models - Exercises - Page 642: 10

Answer

$\begin{array}{|c|r|r|r|r|r|r|r|} \hline x & -3 & -2 & -1 & 0 & 1 & 2 & 3 \\ \hline r(x) &9 &5 & 3 & 2 & 3/2 & 5/4 & 9/8 \\ \hline \end{array}$ Technology formula:$\quad 2$^$(-x)+1\quad$ or $\quad (1/2)$^$x+1$

Work Step by Step

$2^{-x}+1=(\displaystyle \frac{1}{2})^{x}+1$ Technology formula:$\quad 2$^$(-x)+1\quad$ or $\quad (1/2)$^$x+1$ $f(-3)=(\displaystyle \frac{1}{2})^{-3}+1=2^{3}+1=9\qquad $tech:$\qquad (1/2)$^$(-3)+1$ $f(-2)=(\displaystyle \frac{1}{2})^{-2}+1=2^{2}+1=5\qquad $tech:$\qquad (1/2)$^$(-2)+1$ $f(-1)=(\displaystyle \frac{1}{2})^{-1}+1=2+1=3\qquad $tech:$\qquad (1/2)$^$(-1)+1$ $f(0)=2^{0}+1=1+1=2 \qquad $tech:$\qquad 2$^$(-x)+1$ $f(1)=2^{-1}+1=\displaystyle \frac{1}{2}+1=\frac{3}{2} \qquad $tech:$\qquad 2$^$(-1)+1$ $f(2)=2^{-2}+1=\displaystyle \frac{1}{2^{2}}+1=\frac{5}{4} \qquad $tech:$\qquad 2$^$(-2)+1$ $f(3)=2^{-3}+1=\displaystyle \frac{1}{2^{3}}+1=\frac{9}{8} \qquad $tech:$\qquad 2$^$(-3)+1$
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