Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 7 - Section 7.2 - Relative Frequency - Exercises - Page 464: 10

Answer

$0.5125$

Work Step by Step

The first coin lands with heads up: {(HT),(HH)} $P(E)=\frac{fr(E)}{N}=\frac{1100+950}{4000}=\frac{2050}{4000}=0.5125$
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