Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 4 - Review - Review Exercises - Page 296: 3

Answer

The expression is defined, and its value is: $\hphantom {2A^T + C=.} | 1 \space \space \space \space 8| $ $2A^T + C =| 5 \space \space 11| $ $ \hphantom {2A^T + C=.} | 6 \space \space 13| $

Work Step by Step

1. Check if the expression is defined. For a sum operation, both matrices must have the same dimensions. Since $A$ is a $2 \times 3$ matrix, $A^T$ is a $3 \times 2$ one. $C$ is a $3 \times 2$ matrix. Therefore, $2A^T + C$ is a defined expression. 2. Evaluate it: - Transpose A : ($A_{ij} = A^T_{ji}$) $A = | 1 \space \space 2 \space \space 3|$ $ \hphantom {.....} | 4 \space \space 5 \space \space 6|$ $ \hphantom {A^T =.} | 1 \space \space 4|$ $A^T = | 2 \space \space 5|$ $ \hphantom {A^T =.} | 3 \space \space 6|$ - Evaluate ($2A^T$) $\hphantom {22A^T =.} | 1 \space \space 4|$ $2A^T =2| 2 \space \space 5|$ $ \hphantom {22A^T =.} | 3 \space \space 6|$ $\hphantom {2A^T =.} | 1 * 2 \space \space 4*2|$ $2A^T =| 2*2 \space \space 5*2|$ $ \hphantom {2A^T =.} | 3*2 \space \space 6*2|$ $\hphantom {2A^T =.} | 2 \space \space \space \space 8|$ $2A^T =| 4 \space \space 10|$ $ \hphantom {2A^T =.} | 6 \space \space 12|$ - Calculate $(2A^T + C)$ $\hphantom {2A^T + C=.} | 2 \space \space \space \space 8| \hphantom {...}|-1 \space \space 0|$ $2A^T + C =| 4 \space \space 10| + |1 \hphantom {....}1|$ $ \hphantom {2A^T + C=.} | 6 \space \space 12| \hphantom {...}|0 \hphantom {....} 1|$ $\hphantom {2A^T + C=.} | 2 - 1 \space \space \space \space 8 + 0| $ $2A^T + C =| 4 + 1 \space \space 10 + 1| $ $ \hphantom {2A^T + C=.} | 6 + 0 \space \space 12 + 1| $ $\hphantom {2A^T + C=.} | 1 \space \space \space \space 8| $ $2A^T + C =| 5 \space \space 11| $ $ \hphantom {2A^T + C=.} | 6 \space \space 13| $
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