Chapter 2 - Section 2.1 - Simple Interest - Exercises - Page 134: 40

Reading the graph, in 1950, PV= 500 (thousands). In 2010 (t=$60$ years), for r=0.1 (as in exercise 38), we need to find FV $FV=PV(1+rt)=500(1+0.1\cdot 60)=3500$ (thousands) or $3,500,000$

Reading the graph, in 1950, PV= 500 (thousands). In 2010 (t=$60$ years), for r=0.1 (as in exercise 38), we need to find FV $FV=PV(1+rt)=500(1+0.1\cdot 60)=3500$ (thousands) or $3,500,000$