Answer
$6$
Work Step by Step
$f''(x)=\displaystyle \frac{d}{dx}\left[\frac{df}{dx}\right]=\frac{d^{2}f}{dx^{2}}$
$\displaystyle \frac{dy}{dx}=\frac{d}{dx}[3x^{2}-6]= 6x$
$\displaystyle \frac{d^{2}y}{dx^{2}}=\frac{d}{dx}[6x]=6$
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