Answer
$$y=2$$
Work Step by Step
We have: $y= e^x +e^{-x}$
We differentiate both sides with respect to $x$.
$y^{\prime}=e^x-e^{-x}$
Now, $y^{\prime}|_{(0,2)}=1-1\\=0$
The equation of a line is:
$$\dfrac{y-2}{x-0}=0\\\implies y=2$$
Finite Math and Applied Calculus (6th Edition)
by Waner, Stefan; Costenoble, Steven
Published by
Brooks Cole
ISBN 10:
1133607705
ISBN 13:
978-1-13360-770-0
Chapter 11 - Section 11.5 - Derivatives of Logarithmic and Exponential Functions - Exercises - Page 843: 78
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