Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 10 - Section 10.5 - Derivatives: Numerical and Graphical Viewpoints - Exercises - Page 751: 13

Answer

$\displaystyle \frac{1}{2}$

Work Step by Step

The slope of the tangent line through the point on the graph of $f$ where $x=a$ is given by the instantaneous rate of change, or derivative $m_{tan}=$ slope of tangent $=$ instantaneous rate of change$=$derivative $=f^{\prime}(a)=\displaystyle \lim_{h\rightarrow 0}\frac{f(a+h)-f(a)}{h} ,$ assuming the limit exists. -------------- Let P be $(a,f(a))$, since it is on the graph of f. From the graph, we read (estimate) two points from the tangent line at P: (0,2) and (2,3) The slope $m=\displaystyle \frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{3-2}{2-0}=\frac{1}{2},$ so, we estimate $f^{\prime}(a)=m=\displaystyle \frac{1}{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.