Answer
$ - \$ 25,000$ per month
Work Step by Step
The average rate of change of $f(x)$ over the interval $[a, b]$ is $\displaystyle \frac{f(b)-f(a)}{b-a}$
Units: "(unit of f(x) ) per (unit of x)"
--------------
Given the interval $[2,6]$ and the table,
See p.725
The average rate of change of $f(x)$ over the interval $[a, b]$ is $\displaystyle \frac{f(b)-f(a)}{b-a}$
Units: "(unit of f(x) ) per (unit of x)"
--------------
Given the interval $[2,6]$ and the table,
a=$2,\ \quad R(2)=20.2$
b=$6,\ \quad R(6)=20.1$
$\displaystyle \frac{R(b)-R(a)}{b-a} =\displaystyle \frac{20.1-20.2}{6-2}$
$=\displaystyle \frac{-0.1}{4}=-0.025$ (million \$ per month)
$=-\$ 0.025\times 10^{6}$ per month
$=-\$ 25,000$ per month
