Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 10 - Section 10.1 - Limits: Numerical and Graphical Viewpoints - Exercises: 6

Answer

$0$

Work Step by Step

$\lim\limits_{x \to -1} { \frac{x^2+2x+1}{x+1} } = \lim\limits_{x \to -1} { \frac{(x+1)(x+1)}{x+1} } = \lim\limits_{x \to -1} { x+1 } = \lim\limits_{x \to -1} { -1+1 } = 0$
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