Answer
$0$
Work Step by Step
$\lim\limits_{x \to -1} { \frac{x^2+2x+1}{x+1} } = \lim\limits_{x \to -1} { \frac{(x+1)(x+1)}{x+1} } = \lim\limits_{x \to -1} { x+1 } = \lim\limits_{x \to -1} { -1+1 } = 0$
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