#### Answer

$\frac{2x^{2}-1}{x-2}$

#### Work Step by Step

$\frac{2}{\frac{x-2}{x^{2}}}-\frac{1}{x-2}=\frac{2x^{2}}{x-2}-\frac{1}{x-2}=\frac{2x^{2}-1}{x-2}$

Published by
Brooks Cole

ISBN 10:
1133607705

ISBN 13:
978-1-13360-770-0

$\frac{2x^{2}-1}{x-2}$

$\frac{2}{\frac{x-2}{x^{2}}}-\frac{1}{x-2}=\frac{2x^{2}}{x-2}-\frac{1}{x-2}=\frac{2x^{2}-1}{x-2}$

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