## Calculus with Applications (10th Edition)

Published by Pearson

# Prerequisite Skills Diagnostic Test - Page xxiii: 16

#### Answer

$$\frac{a-6}{a+2}$$

#### Work Step by Step

Multiply and factor $$\bigg( \frac{a^2-6a}{a^2-4}\bigg)\bigg(\frac{a-2}{a}\bigg)=$$ Cancel common factors $a$ and $(a-2)$ $$\frac{a(a-6)(a-2)}{(a-2)(a+2)a}=\frac{a-6}{a+2}$$

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