Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter R - Algebra Reference - R.7 Radicals - R.7 Exercises: 7

Answer

$9$

Work Step by Step

$\sqrt{27} \cdot \sqrt{3} \\=\sqrt{9(3)} \cdot \sqrt{3} \\=3\sqrt{3} \cdot \sqrt{3} \\=3 \cdot 3 \\=9$
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