## Calculus with Applications (10th Edition)

$3(m+5)(m^2-5m+25)$
RECALL: $a^3+b^3 = (a+b)(a^2-ab+b^2)$ Factor out $3$ to have: $=3(m^3+125)$ Write $125$ as a cube to have: $=3(m^3+5^3)$ Factor the sum of two cubes using the formula above with $a=m$ and $b=5$ to have: $=3(m+5)[m^2 - m(5) + 5^2] \\=3(m+5)(m^2-5m+25)$