## Calculus with Applications (10th Edition)

Published by Pearson

# Chapter R - Algebra Reference - R.2 Factoring - R.2 Exercises: 30

#### Answer

$3(m+5)(m^2-5m+25)$

#### Work Step by Step

RECALL: $a^3+b^3 = (a+b)(a^2-ab+b^2)$ Factor out $3$ to have: $=3(m^3+125)$ Write $125$ as a cube to have: $=3(m^3+5^3)$ Factor the sum of two cubes using the formula above with $a=m$ and $b=5$ to have: $=3(m+5)[m^2 - m(5) + 5^2] \\=3(m+5)(m^2-5m+25)$

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