Answer
Graph $\mathbf{e}$
Work Step by Step
\[\begin{align}
& {{x}^{2}}-{{y}^{2}}=z \\
& z={{x}^{2}}-{{y}^{2}} \\
& \text{The graph is of the form }z={{x}^{2}}-{{y}^{2}}\text{ which represents a } \\
& \text{hyperbolic paraboloid}.\\
& \text{The equation matches with the graph }\mathbf{e}\text{.} \\
\end{align}\]
