Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 7 - Integration - 7.5 The Area Between Two Curves - 7.5 Exercises - Page 406: 34

Answer

The Consumers’ Surplus is given by: $$ \begin{aligned} \text {Consumers’ surplus }&= \int_{0}^{q_{0}}[D(q)- p_{0}] d q \\ &=\int_{0}^{6}\left[\frac{32,00}{(2 q+8)^{3}}-4\right] d q\\ &= 81 \end{aligned} $$

Work Step by Step

the demand function is given by $$ D(q)=\frac{32,000}{(2 q+8)^{3}}, $$ equilibrium supply $p_0$ is when $q=6$, so we have: $$ \begin{aligned} p_0=D(6)&=\frac{32,000}{(2 (6)+8)^{3}}\\ &=\frac{32,000}{(2 0)^{3}}\\ &=\frac{32,000}{(8,000}\\ &=4 \end{aligned} $$ Now, we know that: $$ \text {Consumers’ Surplus }=\int_{0}^{q_{0}}[D(q)- p_{0}] d q $$ So, the Consumers’ Surplus is given by: $$ \begin{aligned} \text {Consumers’ surplus }&\int_{0}^{q_{0}}[D(q)- p_{0}] d q \\ &=\int_{0}^{6}\left[\frac{32,00}{(2 q+8)^{3}}-4\right] d q\\ &=\int_{0}^{6} \frac{32,00}{(2 q+8)^{3}} d q-\int_{0}^{6} 4 d q \\ &\quad\quad\quad\left[\begin{array}{c}{ \text {Let }u=2q+8, q : 0 \rightarrow 6 } \\ { \text {Then }d u=2d q}, u:8 \rightarrow 20 \end{array}\right] \\ =& \frac{1}{2} \int_{8}^{20} \frac{32,000}{u^{3}} d u-\int_{0}^{6} 4 d q \\=& 16,000 \int_{8}^{20} u^{-3} d u-\int_{0}^{6} 4 d q \\=& 16,\left.00 \cdot \frac{u^{-2}}{-2}\right|_{8} ^{20}-\left.4 q\right|_{0} ^{6} \\=&-\left.\frac{8000}{u^{2}}\right|_{8} ^{20}-24 \\=&-\frac{8000}{400}+\frac{8000}{64}-24 \\=& 81 \end{aligned} $$
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