Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 7 - Integration - 7.5 The Area Between Two Curves - 7.5 Exercises - Page 405: 26

Answer

$3.3829$

Work Step by Step

\[\begin{align} & y=\ln x\text{ and }y={{x}^{3}}-5{{x}^{2}}+6x-1 \\ & \text{Find the intersection points let }y=y \\ & \ln x={{x}^{3}}-5{{x}^{2}}+6x-1 \\ & \text{Using a graphing calculator we obtain:} \\ & {{x}_{1}}=1.402,\text{ }{{x}_{2}}=3.448 \\ & \ln x\ge {{x}^{3}}-5{{x}^{2}}+6x-1\text{ on the interval }\left( 1.402,3.448 \right) \\ & \text{The area between the curves is:} \\ & A=\int_{1.402}^{3.448}{\left[ \ln x-\left( {{x}^{3}}-5{{x}^{2}}+6x-1 \right) \right]}dx \\ & \text{Integrating by a calculator we obtain} \\ & A\approx 3.3829 \\ \end{align}\]
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.