Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 7 - Integration - 7.4 The Fundamental Theorem of Calculus - 7.4 Exercises - Page 396: 60

Answer

The rate at which a substance grows is given by $$ R^{\prime}(x)=150 e^{0.2x} $$ where $x$ is the time (in days). The total accumulated growth during the first 3.5 days is given by: $$ \begin{aligned} \int_{0}^{3.5} R^{\prime}(x) d x &=\int_{0}^{3.5} 150 e^{0.2 x} d x \\ & \approx 760.3 \end{aligned} $$

Work Step by Step

The rate at which a substance grows is given by $$ R^{\prime}(x)=150 e^{0.2x} $$ where $x$ is the time (in days). The total accumulated growth during the first 3.5 days is given by: $$ \begin{aligned} \int_{0}^{3.5} R^{\prime}(x) d x &=\int_{0}^{3.5} 150 e^{0.2 x} d x \\ &=\left.150 \cdot \frac{e^{0.2 x}}{0.2}\right|_{0} ^{3.5} \\ &=\left.750 e^{0.2 x}\right|_{0} ^{3.5} \\ &=750 e^{0.7}-750 e^{0} \\ & \approx 760.3 \end{aligned} $$
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