Answer
Absolute maximum at $x_3$
No absolute minimum
Work Step by Step
Since the range of function =$(-\infty, f(x_3)]$
the maximum = $x_3$
There is no minimum.
Calculus with Applications (10th Edition)
by Lial, Margaret L.; Greenwell, Raymond N.; Ritchey, Nathan P.
Published by
Pearson
ISBN 10:
0321749006
ISBN 13:
978-0-32174-900-0
Chapter 6 - Applications of the Derivative - 6.1 Absolute Extrema - 6.1 Exercises - Page 309: 1
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