Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 5 - Graphs and the Derivative - Chapter Review - Review Exercises - Page 297: 26

Answer

f(x) is decreasing on $(-\infty, 3)$ and increasing on $(3,+\infty)$. On $(-\infty,+\infty)$ f(x) achieves a minimum value of -5 at x=3

Work Step by Step

$f(x) =x^{2}-6x+4$ $f'(x)=2x-6$ $f'(x)=0 \rightarrow 2x-6 =0 \rightarrow x=3$ Thus, f(x) is decreasing on $(-\infty, 3)$ and increasing on $(3,+\infty)$ On $(-\infty,+\infty)$ f(x) achieves a minimum value of -5 at x=3.
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