Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 3 - The Derivative - 3.2 Continuity - 3.2 Exercises - Page 146: 1

Answer

The function is discontinuous at $x = -1$. a) $f(-1)$ does not exist. b) $\frac{1}{2}$ c) $\frac{1}{2}$ d) $\frac{1}{2}$ e) $f$ is not defined at $x=-1$

Work Step by Step

a) The function has a "hole" at $x = -1$, where it does not have a corresponding $y$-value associated with it. b), c), d) If you approach the value of $-1$ from its left or its right, either way, you will get the value of $\frac{1}{2}$ e) The condition not met is that the function must be defined at all points.
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