Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 3 - The Derivative - 3.1 Limits - 3.1 Exercises - Page 135: 2

Answer

a.

Work Step by Step

$\displaystyle \lim_{x\rightarrow 2^{-}}f(x)=\lim_{x\rightarrow 2^{+}}f(x)=-1$, so both the limits from the left and from the right exist, and, they are equal, which means that $\displaystyle \lim_{x\rightarrow 2}f(x)$ exists $\displaystyle \lim_{x\rightarrow 2}f(x)=-1$.
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