## Calculus with Applications (10th Edition)

$\displaystyle \lim_{x\rightarrow 2^{-}}f(x)=\lim_{x\rightarrow 2^{+}}f(x)=-1$, so both the limits from the left and from the right exist, and, they are equal, which means that $\displaystyle \lim_{x\rightarrow 2}f(x)$ exists $\displaystyle \lim_{x\rightarrow 2}f(x)=-1$.