#### Answer

a.

#### Work Step by Step

$\displaystyle \lim_{x\rightarrow 2^{-}}f(x)=\lim_{x\rightarrow 2^{+}}f(x)=-1$, so
both the limits from the left and from the right exist,
and, they are equal,
which means that $\displaystyle \lim_{x\rightarrow 2}f(x)$ exists
$\displaystyle \lim_{x\rightarrow 2}f(x)=-1$.