Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 2 - Nonlinear Functions - 2.4 Exponential Functions - 2.4 Exercises - Page 87: 42


a) $26413.5$ b) $32913.27$ c) $43331.3$

Work Step by Step

In the formula for continuous compounding let $P=\$25.000$ $r=0.055$ a) $t=1$ $A=Pe^{rt}=25000e^{0.055} \approx 26413.5$ b) $t=5$ $A=Pe^{rt}=25000e^{0.055(5)}\approx 32913.27$ c) $t=10$ $A=Pe^{rt}=25000e^{0.055(10)}\approx 43331.3$
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