Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 2 - Nonlinear Functions - 2.2 Quadratic Functions; Translation and Reflection - 2.2 Exercises - Page 66: 59

Answer

(a) The median length of life for people who reach 65, that is, the age for which the survival rate is 0.50. is $87$ years. (b) Find the age beyond which virtually nobody lives. (There are, of course, exceptions.) is $98$ years

Work Step by Step

the survival function for life after 65 is approximately given by: $$ S(x)=1-0.058 x-0.076 x^{2} $$ where $x$ is measured in decades. This function gives the probability that an individual who reaches the age of 65 will live at least $x$ decades ($10x $ years) longer. (a). Find the median length of life for people who reach 65, that is, the age for which the survival rate is 0.50. $$ \begin{aligned} 0.50 &=1-0.058 x-0.076 x^{2}\\ \Rightarrow\\ 0.076 x^{2}+0.058 x -1+ 0.50 &=0\\ 0.076 x^{2}+0.058 x - 0.50 &=0\\ \Rightarrow\\ 76 x^{2}+58 x - 500 &=0\\ 38x^{2}+29x - 250&=0\\ \end{aligned} $$ This does not appear to factor, so we’ll try the quadratic formula: $$ \begin{aligned} x&=\frac{-29 \pm \sqrt{(29)^{2}-4(38)(-250)}}{2(38)}\\ &=\frac{-29 \pm \sqrt{38,841}}{76}\\ x&= \frac{-29-\sqrt{38,841}}{76} \approx-2.97 \\ & \text{and}\\ x&=\frac{-29+\sqrt{38,841}}{76} \approx 2.21\\ & \quad\quad\left[\begin{array}{c}{ \text {We ignore the negative value }} \\ {\text { then} }\end{array}\right] , \\ x&=2.2 \end{aligned} $$ decades $10. x= 10. (2.2)=22 $ years, so The median length of life is 65+22=87 years. (b) Find the age beyond which virtually nobody lives. (There are, of course, exceptions.) If nobody lives, $S(x)=0$ $$ \begin{aligned} 0 &=1-0.058 x-0.076 x^{2}\\ \Rightarrow\\ 0.076 x^{2}+0.058 x -1 &=0\\ 76 x^{2}+58 x - 1000 &=0\\ 38x^{2}+29x - 500&=0\\ \end{aligned} $$ This does not appear to factor, so we’ll try the quadratic formula: $$ \begin{aligned} x &=\frac{-29 \pm \sqrt{(29)^{2}-4(38)(-500)}}{2(38)}\\ &=\frac{-29 \pm \sqrt{76,841}}{76}\\ x&\frac{-29-\sqrt{76,841}}{76} \approx-4.03 \\ & \text{and}\\ x&=\quad \frac{-29+\sqrt{76,841}}{76} \approx 3.27\\ & \quad\quad\left[\begin{array}{c}{ \text {We ignore the negative value }} \\ {\text { then} }\end{array}\right] , \\ x&=3.3 \end{aligned} $$ decades $10. x= 10. (3.3)=33 $ years, so The median length of life is 65+33=98 years.
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