Answer
$c_{2}\approx2.148\cdot 10^{8}$ meters per second.
Work Step by Step
$c_{2}=\frac{c_{1}\sin(\theta_{2})}{\sin(\theta_{1})}$
$c_{2}=\frac{3\cdot 10^{8}\sin(31^{\circ})}{\sin(46^{\circ})}$
$c_{2}\approx2.148\cdot 10^{8}$ meters per second.
Calculus with Applications (10th Edition)
by Lial, Margaret L.; Greenwell, Raymond N.; Ritchey, Nathan P.
Published by
Pearson
ISBN 10:
0321749006
ISBN 13:
978-0-32174-900-0
Chapter 13 - The Trigonometric Functions - 13.1 Definitions of the Trigonometric Functions - 13.1 Exercises - Page 680: 83
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