Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 12 - Sequences and Series - 12.2 Annuities: An Application of Sequences - 12.2 Exercises - Page 621: 9

Answer

142.836

Work Step by Step

We are given $R=1800, n=12\times4=48, i=\frac{0.08}{4}=0.02$ The amount of this annuity is $S=1800[\frac{(1.02)^{48}-1}{0.02}]\approx 142.836$
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