Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 12 - Sequences and Series - 12.1 Geometric Sequences - 12.1 Exercises - Page 613: 41

Answer

On January: $ \$1,073,741,824$ Total amount during January: $ \$2,147,483,647$.

Work Step by Step

We have, January 1: $\$1$ January 2: $\$2$ January 3: $\$4$ The pattern is Geometric sequence with ratio $r=2$. Part 1: We can use formula of nth term of Geometric sequence to find the amount saved on January 31. $\therefore a_n=a_0r^{n-1}$ Where, $a_0$ is first term of sequence Putting $a_0=1$ $r=2$ $n=31$ We get, $a_{31}=(1)(2^{30})=\$1,073,741,824$ Part 2: For total amount we can use summation formula for Geometric sequence, which is, $S_n=\frac{a_0(r^n-1)}{r-1}$ Putting, $n=31,r=2, a_0=1$ We get, $S_{31}=\frac{(1)(2^{31}-1)}{2-1}=\$2,147,483,647$
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