#### Answer

34.31%

#### Work Step by Step

From the normal curve table, the area to the left of $z=-1.17$ is $-0.1210$
From the normal curve table, the area to the left of $z=-0.09$ is $-0.4641$
Therefore, the area to the right is
$P(-1.17\lt Z \lt -0.09)=-0.4641-(-0.1210)=-0.3431$
The proportion is $-0.3431$ or $34.31\%$