Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 1 - Linear Functions - 1.1 Slopes and Equations of Lines - 1.1 Exercises - Page 15: 66

Answer

$v=4.3 \hspace{0.1cm} m/s$

Work Step by Step

Peak vertical force increases linearly with the pony's speed. Let force be denoted as $F $and speed be denoted as $v$. Then we can write the linear function in terms of $(v,F)$ as $F=av+b$ Given two points satisfying this equation as $(2,0.75)$ & $(3,0.93)$. Substituting these points in the above equation and solving we can find the values of a and b. $0.75=2a+b\hspace{0.2cm} ... (1)$ $0.93=3a+b \hspace{0.2cm}...(2)$ subtracting equations $(1)$ and $(2)$ we get, $a=0.18 $ $b=0.39$ Let's substitute the values of a and b in the function to get: $F=0.18v+0.39 ... (3)$ At a critical force, the pony stops trotting and starts to gallop. Given the critical force as $F=1.16$. At $F=1.16$, the speed will be $\frac{1.16-0.39}{0.18}=4.3\hspace{0.1cm} m/s$. (by substituting the value of $F$ in equation $(3)$)
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